Published On Apr 15, 2020
exact df=((variance1 / n1) + (variance2 / n2))^2 / ((1/(n1−1))(variance1/n1)^2 + (1/(n2−1))(variance2/n2)^2)
show more
exact df=((variance1 / n1) + (variance2 / n2))^2 / ((1/(n1−1))(variance1/n1)^2 + (1/(n2−1))(variance2/n2)^2)
